Thrust-to-weight ratio¶
Rockets and landing · level 5, lesson 2 of 6
A question to start¶
A rocket built to leave Mars has a thrust-to-weight ratio of 1.5 when it sits on its pad on Mars. Could it lift off from Earth?
The idea¶
The thrust-to-weight ratio (TWR) is
It tells you at a glance what the engines can do:
- TWR \(> 1\): the rocket can lift off or climb.
- TWR \(= 1\): it can hover.
- TWR \(< 1\): it cannot leave the ground (though it can still speed up in space, where weight does not hold it back).
Starting acceleration. For vertical flight, \(ma = T - mg\), so
A rocket with TWR 1.3 on Earth starts upwards at \(9.81 \times 0.3 = 2.9\) m/s².
On another planet. TWR depends on \(g\). The same rocket has
So the Mars rocket in the question, at 1.5 on Mars, has \(1.5/2.64 = 0.57\) on Earth: it could not lift off from home.
| A rocket with \(T/m\) = 15 m/s² | Mars | Earth | Moon |
|---|---|---|---|
| TWR | 4.0 | 1.5 | 9.3 |
| Starting acceleration upwards | 11.3 m/s² | 5.2 m/s² | 13.4 m/s² |
Why not a huge TWR? Bigger engines are heavier, and a very high TWR crushes the crew and payload with acceleration. Launchers on Earth usually start around 1.2 to 1.5; upper stages, already in space, often have TWR below 1. Landers need TWR a bit above 1 so they can slow down, and must be able to throttle down to hover.
Worked examples¶
1. Saturn V. \(T = 34\) MN, \(m = 2.97 \times 10^6\) kg: TWR \(= 34\times10^6 / (2.97\times10^6 \times 9.81) = 1.17\); \(a = 9.81 \times 0.17 = 1.7\) m/s².
2. The Apollo lunar module's ascent stage. Thrust about 16 kN, mass about 4,700 kg, on the Moon: TWR \(= 16{,}000/(4{,}700 \times 1.62) = 2.1\). The same stage on Mars: \(16{,}000/(4{,}700 \times 3.71) = 0.92\): it could not have left Mars.
3. A throttling lander. A 1,000 kg lander on Mars must hover. It needs \(T = 3{,}710\) N. If its engines can give between 2,000 and 12,000 N, it can hover, slow down hard, or fall a little faster.
Try it¶
- A rocket on Earth has TWR 1.4. Find its starting acceleration.
- The same rocket on Mars: find its TWR and starting acceleration.
- A lander of 3,000 kg must be able to decelerate at 2 m/s² while descending on Mars. What thrust does it need?
- Why do upper stages not need TWR above 1?
- A Mars ascent rocket must lift 20 t from the surface with TWR 1.3 on Mars. What thrust does it need?
Answers
- \(9.81 \times 0.4 = 3.9\) m/s².
- TWR \(= 1.4 \times 2.64 = 3.7\); \(a = 3.71 \times 2.7 = 10.0\) m/s².
- \(T = m(g + a) = 3000 \times 5.71 = 17{,}100\) N.
- They fire already in space, moving sideways near orbital speed; they do not have to hold themselves up against gravity as at lift-off.
- \(T = 1.3 \times 20{,}000 \times 3.71 = 96{,}500\) N, about 97 kN.
Common mistake¶
Thinking TWR is a property of the engine alone. It depends on the whole mass and on the planet's \(g\). As propellant burns, \(m\) falls and TWR rises; on another planet it changes by the ratio of the \(g\) values.
Where it leads¶
- Back: F = ma · Next: Momentum
- Level 5 page · Rockets and landing topic page
- The lander's last seconds: Supersonic retropropulsion.