Electromagnetic induction¶
Electricity and magnetism · level 7, lesson 4 of 6
A question to start¶
Push a magnet into a coil joined to a meter. The needle flicks one way. Pull it out, and the needle flicks the other way. Hold it still, and nothing. Where does the current come from?
The idea¶
A changing magnetic field through a coil makes a voltage in it. This is electromagnetic induction, found by Michael Faraday in 1831.
The magnetic flux through a loop of area \(A\), with the field \(B\) straight through it, is \(\Phi = BA\), in webers (Wb). Faraday's law says the induced voltage (the emf) in a coil of \(N\) turns is
The faster the flux changes, the bigger the voltage. The minus sign is Lenz's law: the induced current flows so as to oppose the change that made it.
A straight wire of length \(L\) moving at speed \(v\) across a field also has an emf: \(\varepsilon = BLv\).
Worked examples¶
1. A coil. 200 turns, area 0.01 m². The field falls from 0.5 T to 0 in 0.1 s: \(\Delta\Phi = 0.005\) Wb, so \(\varepsilon = 200 \times 0.005/0.1 = 10\) V.
2. Faster. The same change in 0.01 s gives 100 V.
3. A moving rod. A 0.5 m rod moves at 4 m/s across a 0.3 T field: \(\varepsilon = 0.3 \times 0.5 \times 4 = 0.6\) V.
Try it¶
- Why does nothing happen when the magnet is held still inside the coil?
- A 50-turn coil of area 0.02 m² sees the field rise from 0 to 0.4 T in 0.2 s. Find the emf.
- Find the emf across a 1.2 m wing of a model plane flying at 20 m/s through a field of \(5\times10^{-5}\) T at right angles.
- What does Lenz's law say about the current induced as the magnet is pushed in?
Answers
- The flux is not changing, so there is no induced voltage.
- \(\Delta\Phi = 0.008\) Wb: \(\varepsilon = 50 \times 0.008/0.2 = 2\) V.
- \(5\times10^{-5} \times 1.2 \times 20 = 1.2\times10^{-3}\) V, 1.2 mV.
- It flows so that the coil's own field pushes back against the incoming magnet.
Common mistake¶
"A strong magnet in a coil makes a current." Only a changing flux does. A magnet sitting still, however strong, induces nothing.